sin(A+B)=sinAcosB+cosAsinB//如何证明?

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sin(A+B)=sinAcosB+cosAsinB//如何证明?
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sin(A+B)=sinAcosB+cosAsinB//如何证明?
sin(A+B)=sinAcosB+cosAsinB//如何证明?

sin(A+B)=sinAcosB+cosAsinB//如何证明?
证明:
如图所示作单位圆,设∠AOC=α,∠COD=β,则∠AOD=α+β,AO=1
作AB⊥Ox交Ox于B,作AC⊥OC交OC于C,作CE⊥AB交AB于E,作CD⊥Ox交Ox于D
易证△OBF∽△ACF
∴∠COD=∠CAF=β
sin (α+β)
=sin∠AOD
=AB/AO
=AB
=AE+EB
=AE+CD
=AO*cosβ+OC*sinβ
=AO*sinαcosβ+AC*cosαsinβ
=sinαcosβ+cosαsinβ

带数字进去,比如30、60、90