设sin(π+α)=4/5,α∈(π/2,3π/2),则sin2α-【cos(a/2)】^2的值为----
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设sin(π+α)=4/5,α∈(π/2,3π/2),则sin2α-【cos(a/2)】^2的值为----
设sin(π+α)=4/5,α∈(π/2,3π/2),则sin2α-【cos(a/2)】^2的值为----
设sin(π+α)=4/5,α∈(π/2,3π/2),则sin2α-【cos(a/2)】^2的值为----
由 sin(π+α)=4/5,得sinα=-4/5,
又α∈(π/2,3π/2),所以 cosα
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