(sinA+sinC)/sinC=根号3是如何转化成〖2sin(A+C)/2×cos(A-C)/2〗/sinC=根号3的?
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![(sinA+sinC)/sinC=根号3是如何转化成〖2sin(A+C)/2×cos(A-C)/2〗/sinC=根号3的?](/uploads/image/z/6867974-38-4.jpg?t=%EF%BC%88sinA%2BsinC%EF%BC%89%2FsinC%3D%E6%A0%B9%E5%8F%B73%E6%98%AF%E5%A6%82%E4%BD%95%E8%BD%AC%E5%8C%96%E6%88%90%E3%80%962sin%28A%2BC%EF%BC%89%2F2%C3%97cos%EF%BC%88A-C%29%2F2%E3%80%97%2FsinC%EF%BC%9D%E6%A0%B9%E5%8F%B73%E7%9A%84%3F)
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