解个三角函数(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)(cos B-1)^2+sin^2 B == 2-2cos B证明左右相等
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![解个三角函数(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)(cos B-1)^2+sin^2 B == 2-2cos B证明左右相等](/uploads/image/z/6998354-26-4.jpg?t=%E8%A7%A3%E4%B8%AA%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%281-2sin+Xcos+X%29%2F%28cos%5E2+X-sin%5E2+X%29+%3D%3D+%281-tan+X%29%2F%281%2Btan+X%29%28cos+B-1%29%5E2%2Bsin%5E2+B+%3D%3D+2-2cos+B%E8%AF%81%E6%98%8E%E5%B7%A6%E5%8F%B3%E7%9B%B8%E7%AD%89)
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解个三角函数(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)(cos B-1)^2+sin^2 B == 2-2cos B证明左右相等
解个三角函数
(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)
(cos B-1)^2+sin^2 B == 2-2cos B
证明左右相等
解个三角函数(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)(cos B-1)^2+sin^2 B == 2-2cos B证明左右相等
(1-2sin Xcos X)/(cos^2 X-sin^2 X)
=(sin^2 X-2sin Xcos X+cos^2 X)/(cos^2 X-sin^2 X)
=(sin X-cos X)^2/(cos X-sin X)(cos X-sin X)
=(cos X-sin X)^2/(cos X-sin X)(cos X+sin X)
=(cos X-sin X)/(cos X+sin X)
=(cos X-cos X*tan X)/(cos X+cos X*tan X)
=cos X(1-tan X)/[cos X(1+tan X)]
=(1-tan X)/(1+tan X)
(cos B-1)^2+sin^2 B
=cos^2 B-2cosB+1+sin^2 B
=cos^2 B+sin^2 B-2cosB+1
=1-2cosB+1
=2-2cosB
解个三角函数(1-2sin Xcos X)/(cos^2 X-sin^2 X) == (1-tan X)/(1+tan X)(cos B-1)^2+sin^2 B == 2-2cos B证明左右相等
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