作业帮log9^8×log4^27=____.
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log9^8×log4^27=____.
log9^8×log4^27=____.
log9^8×log4^27=____.
log9^8×log4^27
=lg8/lg9×lg27/lg4
=3lg2/2lg3×3lg3/2lg2
=3/2×3/2
=9/4
log9^8×log4^27
=lg8/lg9×lg27/lg4
=3/2lg2/lg3×3/2lg3/lg2
=3/2×3/2
=9/4
=2.25
log9^8×log4^27=____.
log4^27×log(8)25×log9^5
log4^27×log(8)25×log9^5
log2 根号2+log9 27+4^log4 13=?
log9×log4
（log2 3+log4 27）*（log3 4+log9 8）=log2的2是下标,后同
（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2）、
计算:log27(32)×log64(27)+log9(2)×log4(√27)=
[log4(3)/log4(8)][log3(2)log9(2)]括号里是真数= = 我写错了 [log4（3）+log8（3）][log3（2）+log9（2）]
log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27)
log2^根号下2+log9^27+4^(log4^13)
计算:(1/4)^log4^1/3-lg25-lg4-log9^27
计算:(log4 3+log8 3)×log9 √2=?
1.log18/25(2/5)2.log4 27×log8 25×log9 5( 8和25是上下并列写的,
谁会这几道log的数学题log4 16 ×log9 8=?3^(2+log32)=?5^(2-log5 3)=?
计算log4(3)*log9(32)
log9 3+log9 27=怎么求~
1把loga^b表示成以b为底的对数2把loga^nb^n表示成以a为底的对数计算 log4^32 log9^8 * lg32^27log4^27/log4^3 (log4^3+log8^3)(log3^2+log9^2)