数学卷附加题:已知数列{an}的前n项和为Sn,且Sn=(n²/2)+(11n/2).数列{bn}满足2b(n+1)=b(n+2)+bn.(3)设f(n)={an,(n=2h-1,h∈N*);bn,(n=2h,h∈N*)}.是否存在m∈N*,使得f(m+15)=5f(m)成立?若存在,求
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![数学卷附加题:已知数列{an}的前n项和为Sn,且Sn=(n²/2)+(11n/2).数列{bn}满足2b(n+1)=b(n+2)+bn.(3)设f(n)={an,(n=2h-1,h∈N*);bn,(n=2h,h∈N*)}.是否存在m∈N*,使得f(m+15)=5f(m)成立?若存在,求](/uploads/image/z/7843510-46-0.jpg?t=%E6%95%B0%E5%AD%A6%E5%8D%B7%E9%99%84%E5%8A%A0%E9%A2%98%EF%BC%9A%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E4%B8%94Sn%3D%28n%26%23178%3B%2F2%29%2B%2811n%2F2%29.%E6%95%B0%E5%88%97%7Bbn%7D%E6%BB%A1%E8%B6%B32b%28n%2B1%29%3Db%28n%2B2%29%2Bbn.%EF%BC%883%EF%BC%89%E8%AE%BEf%EF%BC%88n%EF%BC%89%3D%7Ban%2C%EF%BC%88n%3D2h-1%2Ch%E2%88%88N%2A%EF%BC%89%EF%BC%9Bbn%2C%EF%BC%88n%3D2h%2Ch%E2%88%88N%2A%EF%BC%89%7D.%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8m%E2%88%88N%2A%2C%E4%BD%BF%E5%BE%97f%EF%BC%88m%2B15%EF%BC%89%3D5f%EF%BC%88m%EF%BC%89%E6%88%90%E7%AB%8B%3F%E8%8B%A5%E5%AD%98%E5%9C%A8%2C%E6%B1%82)
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