已知集合A={x|x=3分之k.k∈z},B={x| x=6分之k.k∈Z}则A、A∪≠B B,B∪≠A C,A=B D,A与B关系不确定.

已知集合A={x|x=3分之k.k∈z},B={x| x=6分之k.k∈Z}则A、A∪≠B B,B∪≠A C,A=B D,A与B关系不确定.
已知集合A={x|x=3分之k.k∈z},B={x| x=6分之k.k∈Z}
则A、A∪≠B B,B∪≠A C,A=B D,A与B关系不确定.

已知集合A={x|x=3分之k.k∈z},B={x| x=6分之k.k∈Z}则A、A∪≠B B,B∪≠A C,A=B D,A与B关系不确定.
A={k/3,k∈Z}={..,0,1/3,2/3,1,4/3,...}
B={x=k/6,k∈Z}={..,0,1/6,1/3,1/2,2/3,5/6,1,...}
显然A是B的子集
那么A∪B=B,A∩B=A
我不知道你那个A与B的选项是什么,总之关系就是上面那个.
如果不懂,请Hi我,祝学习愉快!

K.K.[6k$l!kt, -7Wkt] n.Ecclesiastical （名词）【基督教会】 A accu“mulable AHD:[-l…-b…l] （形容词） accumulate 来自拉丁语

The Nike Company has been a long term player and leader within the sports shoe marketplace and has been experiencing a dominating global presence even these days by advertising its goods via large nam...

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