f(x)=sin (ωx+φ)+cos(ωx+φ) =√2sin (ωx+φ+π/4)这步是如何化简过来的!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 07:14:58
![f(x)=sin (ωx+φ)+cos(ωx+φ) =√2sin (ωx+φ+π/4)这步是如何化简过来的!](/uploads/image/z/9282707-35-7.jpg?t=f%28x%29%3Dsin+%28%CF%89x%2B%CF%86%29%2Bcos%28%CF%89x%2B%CF%86%29+%3D%E2%88%9A2sin+%28%CF%89x%2B%CF%86%2B%CF%80%2F4%29%E8%BF%99%E6%AD%A5%E6%98%AF%E5%A6%82%E4%BD%95%E5%8C%96%E7%AE%80%E8%BF%87%E6%9D%A5%E7%9A%84%21)
x)KӨд-S8Y}MS;9V}1IV|3]l˚gu
/?E"}k$d~@9qÄg_.d'>d*:Oz_\"~O4@>Dqħ? 6f@GrBO6]:bZv|>e5O$$$|tqvy:yhF-DN-@ѧ_\g! "O
f(x)=sin (ωx+φ)+cos(ωx+φ) =√2sin (ωx+φ+π/4)这步是如何化简过来的!
f(x)=sin (ωx+φ)+cos(ωx+φ) =√2sin (ωx+φ+π/4)
这步是如何化简过来的!
f(x)=sin (ωx+φ)+cos(ωx+φ) =√2sin (ωx+φ+π/4)这步是如何化简过来的!
f(x)=sin (ωx+φ)+cos(ωx+φ)
【每项乘以一个√2,再除以一个√2(sinπ/4=cosπ/4=1/√2)】得到
=√2cosπ/4sin (ωx+φ)+√2sinπ/4cos(ωx+φ)
=√2[ cosπ/4sin (ωx+φ)+sinπ/4cos(ωx+φ)]
利用公式sinacosb+cosasinb=sin(a+b),本题a=ωx+φ,b=π/4
=√2sin (ωx+φ+π/4)
函数f(x)=sin (ωx+φ)+cos(ωx+φ)(ω>0,|φ|
设偶函数f(x)=sin (ωx+φ)+cos(ωx+φ)(ω>0,|φ|
设偶函数f(x)=sin (ωx+φ)+cos(ωx+φ)(ω>0,|φ|
已知函数f(x)=√3sin(ωx+φ)-cos(ωx+φ)(0
已知函数f(x)=√3sin(ωx+φ)-cos(ωx+φ)(o
f'(sin x)=1-cos x 求f''(x)
f(x)=sin²ωx+√3cosωx*cos(π/2-ωx)化简成f(x)=Asin(ωx+φ)+b的形式
函数f(x)=sin(x)+cos(x)-sin(x)*cos(x)的值域是什么
f(x)=sin x +cos x +sin x * cos x ,求值域
f(sin x)=cos2X 那么f(cos x)=
f(x)=cos(2x)+2sin(x)化简
F(X)=SIN X+COS X展开的幂级数
求f(x)=|sin x|+|cos x|的周期
f(x)=sin³x-cos³x
f(x)=sin x+cos x的奇偶性,
f'(sin^2x)=cos^2x,求f(x)f'((sin^x)^2)=(cos^x)^2
若f(sin x+cos x)=sin x·cos x,则f(cos 派/6)=?
函数f(x)=sin(2x+π/6),g(x)=cos(x+φ),|φ|