f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1 f''(x)f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1f''(x)=4e^2x–1不明白e前面的2是怎样来的?
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![f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1 f''(x)f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1f''(x)=4e^2x–1不明白e前面的2是怎样来的?](/uploads/image/z/9301186-10-6.jpg?t=f%28x%29%3De%5E2x%EF%BC%8D1+f%27%27%280%29%3D%3Ff%27%28x%29%3D2e%5E2x%E2%80%931+f%27%27%28x%29f%28x%29%3De%5E2x%EF%BC%8D1+f%27%27%280%29%3D%3Ff%27%28x%29%3D2e%5E2x%E2%80%931f%27%27%28x%29%3D4e%5E2x%E2%80%931%E4%B8%8D%E6%98%8E%E7%99%BDe%E5%89%8D%E9%9D%A2%E7%9A%842%E6%98%AF%E6%80%8E%E6%A0%B7%E6%9D%A5%E7%9A%84%3F)
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f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1 f''(x)f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1f''(x)=4e^2x–1不明白e前面的2是怎样来的?
f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1 f''(x)
f(x)=e^2x-1 f''(0)=?
f'(x)=2e^2x–1
f''(x)=4e^2x–1
不明白e前面的2是怎样来的?
f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1 f''(x)f(x)=e^2x-1 f''(0)=?f'(x)=2e^2x–1f''(x)=4e^2x–1不明白e前面的2是怎样来的?
那个2是对 2x进行的
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