拉格朗日乘数法求函数极值问题.急大一学的东西 有点忘了举个最简单的例子f(x,y)=x+y subject to the constraint:2x+y^2 -5=0define the lagrange functionL(x,y)=x+y+λ(2x+y-5)partial derivertive:d(L)/d(x)=1+2λ=0d(L)/d(y)=1+λy
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 04:50:52
![拉格朗日乘数法求函数极值问题.急大一学的东西 有点忘了举个最简单的例子f(x,y)=x+y subject to the constraint:2x+y^2 -5=0define the lagrange functionL(x,y)=x+y+λ(2x+y-5)partial derivertive:d(L)/d(x)=1+2λ=0d(L)/d(y)=1+λy](/uploads/image/z/9487250-26-0.jpg?t=%E6%8B%89%E6%A0%BC%E6%9C%97%E6%97%A5%E4%B9%98%E6%95%B0%E6%B3%95%E6%B1%82%E5%87%BD%E6%95%B0%E6%9E%81%E5%80%BC%E9%97%AE%E9%A2%98.%E6%80%A5%E5%A4%A7%E4%B8%80%E5%AD%A6%E7%9A%84%E4%B8%9C%E8%A5%BF+%E6%9C%89%E7%82%B9%E5%BF%98%E4%BA%86%E4%B8%BE%E4%B8%AA%E6%9C%80%E7%AE%80%E5%8D%95%E7%9A%84%E4%BE%8B%E5%AD%90f%28x%2Cy%29%3Dx%2By+subject+to+the+constraint%3A2x%2By%5E2+-5%3D0define+the+lagrange+functionL%28x%2Cy%29%3Dx%2By%2B%CE%BB%282x%2By-5%29partial+derivertive%3Ad%28L%29%2Fd%28x%29%3D1%2B2%CE%BB%3D0d%28L%29%2Fd%28y%29%3D1%2B%CE%BBy)
拉格朗日乘数法求函数极值问题.急大一学的东西 有点忘了举个最简单的例子f(x,y)=x+y subject to the constraint:2x+y^2 -5=0define the lagrange functionL(x,y)=x+y+λ(2x+y-5)partial derivertive:d(L)/d(x)=1+2λ=0d(L)/d(y)=1+λy
拉格朗日乘数法求函数极值问题.急
大一学的东西 有点忘了
举个最简单的例子
f(x,y)=x+y subject to the constraint:2x+y^2 -5=0
define the lagrange function
L(x,y)=x+y+λ(2x+y-5)
partial derivertive:
d(L)/d(x)=1+2λ=0
d(L)/d(y)=1+λy=0
d(L)/d(λ)=2x+y-5=0
最底下着三个方程组是怎么的出来的
f(x,y)= C ln x1+d ln x2
P1X1+P2X2=M
如果问题是这样,这个方程组应该是什么
拉格朗日乘数法求函数极值问题.急大一学的东西 有点忘了举个最简单的例子f(x,y)=x+y subject to the constraint:2x+y^2 -5=0define the lagrange functionL(x,y)=x+y+λ(2x+y-5)partial derivertive:d(L)/d(x)=1+2λ=0d(L)/d(y)=1+λy
L(x,y) 分别对x,y,λ 求偏导
L(x,y)=C ln x1+d ln x2+λ (P1X1+P2X2-M)
分别对x1,x2,λ 求偏导
d(L)/d(x1)=c/x1+λp1=0
d(L)/d(x1)=d/x2+λp2=0
d(L)/d(x1)=P1X1+P2X2-M=0
d(L)/d(x)=1+2λ=0
d(L)/d(y)=1+λy=0
d(L)/d(λ)=2x+y-5=0
很简单,是分别根据以x,y,λ为自变量对因变量L进行求一阶导数。