填空题lim(n→∞)= √(3n^2+6n+5)/(3n-2)=____这题怎么计算啊?

填空题lim(n→∞)= √(3n^2+6n+5)/(3n-2)=____这题怎么计算啊? 用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4 极限 lim(n→∞)[(n!)^2/(2n)!]= 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(n→∞)(2n-1/n+3) lim(n→∞) 2^n/n!=0 极限lim(n→∞)√(n^2-3n)/2n+1 等于多少 lim n→∞ n/√(2n+1)(n+1)= lim n--∞ (1+2/n)^n=?如题 lim n→∞ n^(3/2)* (n+1)^(1/2)* (1-cos(π/n))=? n→∞ lim(n+3/n+1)^2n= lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞ 用夹逼定理求lim(n→∞)[√(n^2+n)-n]^(1/n) 用夹逼定理求lim(n→∞)√[(n^2+n)-n]^(1/n) ε-N定义证明 lim(n→∞)(3n^2+n)/(2n^2-1)=3/2, lim（n→∞）(3n^3-2n+1)/n^3+n^2 快 高数题:lim(n→∞)(1+2∧n+3∧n+4∧n)∧ 1/n=?