1.已知x+y+z=6,xy+yz+xz=7,则x²+y²+z²=?2.(2a+2b+1)(2a+2b-1)=63,则a+b=?3.已知x²+y²=5,x-y=2,求(x+y)²的值为?4.(a-2b+3)(a+2b-3) 5.2002²-2001×2003=?6.求值:(1)已知(x+y)²=20,(x-y)²=40求x&s
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