代数不等式1设x、y、z∈R+,求证：x√[x/(1+yz)]+y√[y/(1+zx)]+z√[z/(1+xy)]≥3/√(1+xyz).

代数不等式1设x、y、z∈R+,求证：x√[x/(1+yz)]+y√[y/(1+zx)]+z√[z/(1+xy)]≥3/√(1+xyz). 代数不等式（1）设x,y,z为正实数求证 3（x^3*y+y^3*z+z^3*x)= 不等式的 已知x,y,z∈R,且x+y+z=1,求证√x+√y+√z 设x,y,z∈R+.求证:x^4+y^4+z^4≥(x+y+z)xyz 设x,y,z∈,R求证：x²+xz+z²+3y(X+y+z)≥0 设x,y,z∈R+,且3^x=4^y=6^z.求证1/z-1/x=1/2y. 设x,y,z∈R+,xy+yz+xz=1,证明不等式:(xy)^2/z+(xz)^2/y+(yz)^2/x+6xyz≥x+y+zRt 设 x,y∈R ,且3^x=4^y=6^z,求证 1/z - 1/x =1/2y . 数学高一不等式的问题x,y,z∈R且x+y+z=1,x^2+y^2+z^2=1,x>y>z,求证:-1/3 用柯西不等式证明：设正数x,y,z,满足x+y+z=1,求证:1/x+4/y+9/z≥36 设x,y,z属于R+,求证:x^4+y^4+z^4=(x+y+z)xyz 已知x,y,z∈R,求证:x^2+y^2>=xy+x+y-1 设x,y,z∈R+,求证 2z2-x2-y2/(x+y)+2x2-y2-z2/(y+z)≥x2+z2-2y2/(x+z) 设x,y,z∈R+,求证 2z2-x2-y2/(x+y)+2x2-y2-z2/(y+z)≥x2+z2-2y2/(x+z) 不等式选讲的题目1.设x、y、z为实数,证明:|x|+|y|+|z|≤|x+y-z|+|x-y+z|+|y+z-x|已知x、y、z∈R,且x+y+z=8,x^2+y^2+z^2=24,求证:4/3≤x,z≤3已知a,b,c为正实数,且ab+bc+ca=1.求a+b+c-abc的最小值（2）证明a^2/(a^2+1)+b^2/( 设x,y,z∈R,2x+2y+z+8=0,则(x-1)2+(y+2)2+(z-3)2最小值是关于柯西不等式的. 高一数学必修五基本不等式设x,y,z∈R+,且满足x-2y+3z=0,则y²/xz的最小值 数学不等式题：x.y.z属于R+,xyz(x+y+z)=1 求（x+y)(y+z)最小值