y''+y'=y'y x=2时,y=x,y'=1/2,求通解
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x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
y+y'-2y=2x
微分方程y - 2y' + y = x
化简 x / y(x+y) - y / x(x+y) =
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x(x+y)(x-y)-y(y+x)(y-x)=(x-y)( )填空
当x+y=2时7(x+y)一(x+y)+(x+y)=?
填空:x-y/x+y=( )/x^2-y^2
(x-y)2•(y-x)³(x-y)=?
:y' +y= cos x y=
(x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
求y'=y/(y-x)
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
y''+y'=y'y x=2时,y=x,y'=1/2,求通解
(x-4y)(2x+y)=
(x+y)(2x-3y)=?