(√2)/2·sin 45°+sin 30°=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 14:14:34
x){Q,{:m/S01=A068&HUv6Ěfmodkm@ QJ
(√2)/2·sin 45°+sin 30°=?
计算:sin²1°+sin²2°+sin²3°...+sin²45°+sin²46°...+sin²89°
sin²1°+sin²2°+sin²3°+.+sin²89
傅里叶级数作图f(x)=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si
计算:sin²1°+sin²2°+sin²3°+...+sin²87°+sin²88°+sin²89°
sin²1°+sin²2°+sin²3°+……+sin²87°+sin²88°+sin²89°=
sin²1°+sin²2°+sin²3°+...+sin²88°+sin²89°+sin²90°=等于多少?
3 在三角形ABC中,已知(a2+b2)sin(A-B)=(a2-b2)sin(A+B) 求证:ABC是等腰或直角三角形(a^2+b^2)sin(A-B)=(a^2-b^2)sin(A+B),(sin^A+sin^B)sin(A-B)=(sin^A-sin^B)sin(A+B) sin^A*(sin(A+B)-sin(A-B))=sin^B*(sin(A-B)+sin(A+B)) sin^A*2c
sin²1°+sin²2°+sin²3°+···+sin²88°+sin²89°+sin²90°的值为多少?
求值:(tan10°-√3)×cos10°/sin50° 求证:[sin(2α+β)]/sinα- 2cos(α+β)=sinβ/cosα 化简cosθ+cos(θ+2π/3)+cos(θ+4π/3) 证明:sin(α+β)sin(α-β)=sin^2α-sin^2β
2sin(α+π/3)=sinα+______
尽快 我今天将就要!化简(计算)1、Sin²10°+Sin²20°+Sin²30°+Sin²40°+Sin²50°+Sin²60°+Sin²70°+Sin²80°+Sin²90°2、√(Sin44°-Cos44°)²3、√ 1-2Sim50°Cos50°4、tan41°*tan42°*
高一三角函数题目,求解啊~~已知tanα=2(1)2sin²α-sinα·cosα/sin²α-2cos²α(2)√3·cosα+2sinα(3)2sin²α+sin·cosα/sin²α+5(4)sin²α+sinα·cosα+3各位数学天才帮我解下,谢谢
sin x=sin(45+x)×(根2÷3)sin x=sin(45-x)×(根2÷3)
sin(平方)1°×sin(平方)2°×sin(平方)3°.sin(平方)89°得多少?
初三数学(三角函数1)1、求sin²1°+sin²2°+sin²3°+……+sin²89°的值.
sin²1°+sin²2°+sin²3°……sin²89°=?
sin²1°+sin²2°+sin²3°……sin²89°=