log2^x=-(x-4)^2是否有解?lg(x+2)=2^x是否有解
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log2^x=-(x-4)^2是否有解?lg(x+2)=2^x是否有解
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f(x)=log2(2x)×log2(x/4)=[(log2 2)+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2
解不等式2log2 (x-4)< log2 (x-2)
解不等式log2(4x+8)>log2(2x+1)
解方程log2(2-x)=log2(x-1)+1
解2log2^(x-5)=log2^(x-1)+1
化简:(log2(x/4))*(log2(x/2))
log2 (x+4)=2x有两个根,
解方程log2^(4^x+4)=x+log2^[2^(x+1)-3]
解方程:log2(4^x+4)=x+log2(2^(x+1)-3)
解方程log2(4^x+1)=x+log2(2^(x+3)-6)
谁能帮我解一下:log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
解方程:log2(x+4)+log2(x-1)=1+log2(x+8)
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
解不等式log2(4x-x^2)
x^(log2 x)=32x^4 log2 x 2在下面x^(log2 x)=32x^4 log2 x 2在下面
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1