证明∫sin(x^2)dx=0.5√(π/2),积分区间为0到正无穷.

证明∫sin(x^2)dx=0.5√(π/2),积分区间为0到正无穷. 证明∫(0,π/2)sin^m x dx=∫(0,π/2)cos^m x dx 证明∫( 0,π／2 ) (f sin x/(f sin x+f cos x) dx=π /4 证明∫sin(x^2) dx >0 积分区间为0到√(pi/2) ∫sin(√2x)dx ∫sin(6x)sin(2x)dx=? ∫(2/sin^2x)dx= 求不定积分 ∫ dx / √x sin^2 √x dx = 证明∫xf(sin x)dx=π/2∫f(sin x)dx 积分区间都是0到π我自己反复用代换做过了但是一直卡住。 证明∫(0,π/2)sin^m x cos^m x dx=1/2^m∫(0,π/2)cos^m xdx 证明∫(0,π/2)sin^m x cos^m x dx=1/2^m∫(0,π/2)cos^m xdx ∫(cot^2 x/sin^2 x)dx=? ∫sin^3(x)cos^2(x)dx= ∫x/sin^2(x) dx ∫sin(x) cos^2(x)dx ∫sin(2x+1)dx=?· ∫1/(1+x^2)dx= 已知∫(0,+∞)e^[-(x^2)]dx=√π/2,证明∫(-∞,+∞)x^2e^[-(x^2)]dx=√π/2,求详解. 求∫√(sin^3x-sin^5x)dx