3tanx=2tan(2x+y) 求证:sin(2x+y)=5siny
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 21:45:46
![3tanx=2tan(2x+y) 求证:sin(2x+y)=5siny](/uploads/image/z/10153805-5-5.jpg?t=3tanx%3D2tan%282x%2By%29+%E6%B1%82%E8%AF%81%EF%BC%9Asin%EF%BC%882x%2By%EF%BC%89%3D5siny)
3tanx=2tan(2x+y) 求证:sin(2x+y)=5siny
3tanx=2tan(2x+y) 求证:sin(2x+y)=5siny
3tanx=2tan(2x+y) 求证:sin(2x+y)=5siny
3tanx=2tan(2x+y)
两边同乘以cosx cos(2x+y):
3sinx cos(2x+y) = 2sin(2x+y) cosx
6sinx cos(2x+y) = 4sin(2x+y) cosx
6sinx cos(2x+y) + sinx cos(2x+y) = 4sin(2x+y) cosx - sin(2x+y) cosx
sinx cos(2x+y) + sin(2x+y) cosx = 5sin(2x+y) cosx - 5sinx cos(2x+y)
sinx cos(2x+y) + cosx sin(2x+y) = 5sin(2x+y) cosx - 5cos(2x+y)sinx
sin(x+2x+y) = 5 sin(2x+y-x)
sin[2(x+y)] = 5 sin(x+y)
题目条件不正确.
如果条件改为【3tanx=2tan(x+y) 】
两边同乘以cosx cos(x+y):
3sinx cos(x+y) = 2sin(x+y) cosx
6sinx cos(x+y) = 4sin(x+y) cosx
6sinx cos(x+y) + sinx cos(x+y) = 4sin(x+y) cosx - sin(x+y) cosx
sinx cos(x+y) + sin(x+y) cosx = 5sin(x+y) cosx - 5sinx cos(x+y)
sinx cos(x+y) + cosx sin(x+y) = 5sin(x+y) cosx - 5cos(x+y)sinx
sin(x+x+y) = 5 sin(x+y-x)
sin(x+y) = 5 siny