若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少

来源：学生作业帮助网编辑：作业帮时间：2024/11/24 18:38:41

x��Q�N�0��

若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少
若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少

若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少
tan(2x+y)=tan[(x+y)+x]
tan(2x+y)=[tan(x+y)+tanx]/[1-tan(x+y)tanx]
3=[tan(x+y)+5]/[1-5tan(x+y)]
3-15tan(x+y)=tan(x+y)+5
16tan(x+y)=-2
tan(x+y)=-1/8

tan(2x)=2*tan(x)/(1-tanx*tanx)=-5/12
tan(2x+y)=3
=(tan(2x)+tany)/(1-tan2x*tany)=3
tany=-41/3
tan(x+y)=(tanx+tany)/(1-tanx*tany)=-1/8

设所求为n
tan(2x+y)=【n+tanx】/【1-ntanx】
n=-1/8

tan(2x+y)=[tanx+tan(x+y)]/[1-tanx*tan(x+y)]=3
[5+tan(x+y)]/[1-5*tan(x+y)]=3
[5+tan(x+y)]=3-15*tan(x+y)
tan(x+y)=-1/8

*为乘号

若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少已知5siny=sin(2x+y),求证:tan(x+y)=3/2tanx 若tanx=1/2,tan(x-y)==-2/5,则tan(2x-y) 求函数y=tan^2-tanx+1/tan^x+tanx+1的值域谢谢了, 若tanx=2,tany=3,求tan(x-y) tanx=2,tan(x-y)=-3/5,则tany=? 函数y=5/(2tan^x-4tanx+3)的值域是 tan(x+y)=tanx+tany吗 y=tan^2x-tanx+1的奇偶性 tan(x+y)=7,tanx*tany=2/3,则cos（x-y）=? 3sinX=sin(2X+Y) 求证：tan(X+Y)=2tanX 已知：3sinY=sin(2X+Y),求证tan(X+Y)=2tanX cos(2x+y)=3cosy,求tanx*tan(x+y) 若tan（x+y）=2tanx,求证3siny=sin（2x+y）. 3tanx=2tan(2x+y) 求证：sin（2x+y）=5siny 求解一道三角函数体已知sin(2x+y)=5siny,求证2tan(x+y)=3tanx. 求函数y=tan^2x-tanx+1/tan^2x+tanx+1的最大值与最小值求函数值域y=tan^2x-2tanx x属于[-π/3,π/3]