已知(x+y)^2n=1/8,(x-y)^n=4,求[(x+y)(x-y)]^4n的值

来源：学生作业帮助网编辑：作业帮时间：2024/07/02 10:41:15

x��)�{�}��K5*�+5��l �-t4*t��<[�g��R`��8��Z�6�I*�'S�~�� %�jT�� T�a�� c��=�P�L�r@IM5eCsk�:3��^�5h{aM�Ll�ʑ�DC��(�F�1��hd�bm m��젞�s4"�#5�~�80��{z �ЅH��3�裎-hb3E�d�� vKѴ�M��I$�a�ѰX��3Ҋ�� PT��Z&0��F�f� VC�AD�BX0�{�-�

已知(x+y)^2n=1/8,(x-y)^n=4,求[(x+y)(x-y)]^4n的值
已知(x+y)^2n=1/8,(x-y)^n=4,求[(x+y)(x-y)]^4n的值

已知(x+y)^2n=1/8,(x-y)^n=4,求[(x+y)(x-y)]^4n的值
(x＋y)^(2n)=1/8,则：
(x＋y)^(4n)=(1/8)²=1/64
(x－y)^n=4,则：
(x－y)^(4n)=4^4=64
则：
[(x＋y(x－y)]^(4n)=[(x＋y)^(4n)]×[(x－y)^(4n)]=1

(X+Y)^4n=(1/8)^2=1/64，
(X-Y)^4n=4^4n=64,
∴[(x+y)(x-y)]^4n=(X+Y)^4n*(X-Y)^4n=1/64*64=1

[(x+y)(x-y)]^4n
=(x+y)^4n(x-y)^4n
=[(x+y)^2n]^2*[(x-y)^n]^4
=(1/8)^2*4^4
=1/64*256
=4

(x+y)^4n=1/64
x-y)^4n=64
[(x+y)(x-y)]^4n=1

已知(x+y)^2n=1/8,(x-y)^n=4,求[(x+y)(x-y)]^4n的值已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0 已知x=-8,y=8分之一,n为正整数,求x^2n+1×y^2n+1 已知M={y|y=x²-4x+3,x∈R},N={y|y=-x²+2x+8,x∈R},求M∩N 答案是{y|-1≤y≤9} 已知x,y是实数,集合m{x,y已知x,y是实数,集合m={x,y/x,1},n={x^2,x+y,0}.若m=n,求x^2012+y^2012的值已知 8x^2y^3 与 -3x^m+1y^n+1 是同类项,则m+n= 已知M=(x,y)|y>=x2 N=(x,y)|x2+(y-a)2 已知实数x,y满足x+y=1,n∈N+,求证x^2n+y^2n≥1/2^(2n-1) 已知集合M={(x,y)|2x+y=2},N={(x,y)|x-2y=8} 那么M∩N= 已知集合M={(x,y)|y=x+1},N={(x,y)|x^2+y^2=1},则集合M交N中元素有几个? 已知集合M=｛y|y=x²-2x+3｝,N=｛y|y=2x²-3x+1｝则M∪N= 已知集合M={(x,y)|y=x+1},N={(x,y)||x|+y=2},则集合M∩N中元素的个数是? 已知抛物线y=-1/2x^2-(n+1)x-2n (n 已知抛物线y=-1/2x²-(n+1)x-2n(n 已知抛物线y=-1/2x²-(n+1)x-2n(n 已知抛物线y=-0.5x^2-(n+1)x-2n(n 已知(3x^2y^m)^2除以(2x^my)^3=(3x^2y^n)^2除以(2x^n-1y^n)^3 已知x^n=5,y^n=3,求(x^2y)^2n