∫x/[(sinx)^2]dX=
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 09:15:32
![∫x/[(sinx)^2]dX=](/uploads/image/z/11457584-8-4.jpg?t=%E2%88%ABx%2F%EF%BC%BB%EF%BC%88sinx%EF%BC%89%EF%BC%BE2%EF%BC%BDdX%EF%BC%9D)
xMN0T'(6ATp.knFz:PN99s9ruۮԽq݃){{5VnYBv>yc-wy-feN#g1i4FP0n;-+nk脒ն
bβdaE-FÖəة[~oO%^
∫x/[(sinx)^2]dX=
∫x/[(sinx)^2]dX=
∫x/[(sinx)^2]dX=
∫x/[(sinx)^2]dX=
∫(sinx-x^2)dx
∫x/(sinx)^2dx
∫ x/(sinx)^2dx
∫(sinx)2 dx=?
∫(sinx)2 dx=?
∫(x/2+e^x+sinx)dx
∫(2x-1)除以根号x dx ∫cosx dx +∫-2(sinx)^2 乘以cosx dx+∫(sinx)^4乘以cosx dx
∫ arccos7x dx∫ xcos(2-x) dx∫ sinx/(5+3sinx) dx
2 ∫ sinx/1+x²dx=( ) -2
计算定积分,∫sinx(2-3x)dx
求∫1到5(|2-x|+|sinx|)dx
∫[(1+cos2x)^1/2]+[|x|(sinx)^3] dx
∫(上限5,下限1)(|2-x|+|sinx|)dx
∫x∧5(sinx)∧2dx
∫x(sin2x-sinx)dx
求∫(sinx/x)dx
∫(1+sinx) / cos^2 x dx