已知函数f(x)=sinx+2xf′(π/3),则f′(π/3﹚=

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已知函数f(x)=sinx+2xf′(π/3),则f′(π/3﹚=
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已知函数f(x)=sinx+2xf′(π/3),则f′(π/3﹚=
已知函数f(x)=sinx+2xf′(π/3),则f′(π/3﹚=

已知函数f(x)=sinx+2xf′(π/3),则f′(π/3﹚=
f(x)=sinx+2xf′(π/3)
两边求导得:
f'(x)=cosx+2f'(π/3)
令x=π/3,则:f'(π/3)=cos(π/3)+2f'(π/3)
得:f'(π/3)=-1/2