求cos2α-cos2β化为sin(α+β)sin(β-α)的过程,
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求cos2α-cos2β化为sin(α+β)sin(β-α)的过程,
求cos2α-cos2β化为sin(α+β)sin(β-α)的过程,
求cos2α-cos2β化为sin(α+β)sin(β-α)的过程,
求cos2α-cos2β化为sin(α+β)sin(β-α)的过程,
sin²α*sin²β+cos²α*cos²β-1/2cos2αcos2β=(1-cos2α)/2*(1-cos2β)/2+(1+cos2α)/2*(1+cos2β)/2-1/2cos2α*cos2β=1/4(1+cos2α*cos2β-cos2α-cos2β)+1/4(1+cos2α*cos2β+cos2α+cos2β)-1/2cos2α*cos2β=1/4+1/
sinα+sinβ=1.cosα+cosβ=0求cos2α+cos2β
化简sinα^2sinβ^2+cos^2cosβ^2-1/2cos2αcos2β
cos2α+cos2β等于多少?
已知cos2α-cos2β=1/4,那么sin(α+β)sin(α-β)=?
求证:cos2αcos2β=1/2{cos2(α+β)+cos2(α-β)}
2cos2αcos2β如何化成cos2(α+β)+cos2(α-β)
化简:(sinα)^2+(sinβ)^2-(sinα)^2(sinβ)^2+cos2αcos2β
sinα-cosα=1/2 求cos2α
一道高一三角函数求值题.已知cosα+cosβ+cosγ=0 ,且sinα+sinβ+sinγ=0求cos2(α-β)+cos2(β-γ)+cos2(γ-α)的值
化简:sinαcosαcos2α
sinαcosαcos2α化简
sinαcosαcos2α=
化简:sin²αsin²β+cos²αcos²β-1/2cos2αcos2β
化简(sinα)^2*(sinβ)^2+(cosα)^2(cosβ)^2-1/2cos2αcos2β
化简 sin²αsin²β+cos²αcos²β-1/2(cos2αcos2β)
sin²αsin²β+cos²αcos²β-【(1/2)*cos2αcos2β】