设数列bn满足:b1=1/2,bn+1=bn^2+bn1)求证:bn+1/1=bn/1-bn+1/1 2)若tn=b1+1/1+b2+1/1+.+bn+1/1,求Tn的最小值只解第二问就行tn=b1+1/1+b2+1/1+......+bn+1/1,求Tn的最小值
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![设数列bn满足:b1=1/2,bn+1=bn^2+bn1)求证:bn+1/1=bn/1-bn+1/1 2)若tn=b1+1/1+b2+1/1+.+bn+1/1,求Tn的最小值只解第二问就行tn=b1+1/1+b2+1/1+......+bn+1/1,求Tn的最小值](/uploads/image/z/13337990-62-0.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97bn%E6%BB%A1%E8%B6%B3%EF%BC%9Ab1%3D1%2F2%2Cbn%2B1%3Dbn%5E2%2Bbn1%29%E6%B1%82%E8%AF%81%EF%BC%9Abn%2B1%2F1%3Dbn%2F1-bn%2B1%2F1+2%29%E8%8B%A5tn%3Db1%2B1%2F1%2Bb2%2B1%2F1%2B.%2Bbn%2B1%2F1%2C%E6%B1%82Tn%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E5%8F%AA%E8%A7%A3%E7%AC%AC%E4%BA%8C%E9%97%AE%E5%B0%B1%E8%A1%8Ctn%3Db1%2B1%2F1%2Bb2%2B1%2F1%2B......%2Bbn%2B1%2F1%2C%E6%B1%82Tn%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC)
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