已知,(√X²+25+10X)+(√49+X²-14X)=12,试化简√(3X+15)²+3|7-X|X²+25+10X和49+X²-14X和(3X+15)²都在根号下我在学二次根式,
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![已知,(√X²+25+10X)+(√49+X²-14X)=12,试化简√(3X+15)²+3|7-X|X²+25+10X和49+X²-14X和(3X+15)²都在根号下我在学二次根式,](/uploads/image/z/1339960-40-0.jpg?t=%E5%B7%B2%E7%9F%A5%2C%28%E2%88%9AX%26%23178%3B%2B25%2B10X%29%2B%28%E2%88%9A49%2BX%26%23178%3B-14X%29%3D12%2C%E8%AF%95%E5%8C%96%E7%AE%80%E2%88%9A%283X%2B15%EF%BC%89%26%23178%3B%2B3%7C7-X%7CX%26%23178%3B%2B25%2B10X%E5%92%8C49%2BX%26%23178%3B-14X%E5%92%8C%EF%BC%883X%2B15%EF%BC%89%26%23178%3B%E9%83%BD%E5%9C%A8%E6%A0%B9%E5%8F%B7%E4%B8%8B%E6%88%91%E5%9C%A8%E5%AD%A6%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%2C)
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已知,(√X²+25+10X)+(√49+X²-14X)=12,试化简√(3X+15)²+3|7-X|X²+25+10X和49+X²-14X和(3X+15)²都在根号下我在学二次根式,
已知,(√X²+25+10X)+(√49+X²-14X)=12,试化简√(3X+15)²+3|7-X|
X²+25+10X和49+X²-14X和(3X+15)²都在根号下
我在学二次根式,
已知,(√X²+25+10X)+(√49+X²-14X)=12,试化简√(3X+15)²+3|7-X|X²+25+10X和49+X²-14X和(3X+15)²都在根号下我在学二次根式,
X²+25+10X=(X+5)²,49+X²-14X=(X-7)²,所以已知式子化为|X+5|+|X-7|=12,所以x大于等于-5,小于等于7,所以要化解的式子化为3X+15+3(7-x)=36