AB=DC,DF=BE,AF=CE,求证:(1)△ABE≌CDF;(2)DC∥AB.
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AB=DC,DF=BE,AF=CE,求证:(1)△ABE≌CDF;(2)DC∥AB.
AB=DC,DF=BE,AF=CE,求证:(1)△ABE≌CDF;(2)DC∥AB.
AB=DC,DF=BE,AF=CE,求证:(1)△ABE≌CDF;(2)DC∥AB.
(1)∵AF=CE
∴AF-EF=CE-EF
即:AE=CF
在△CDF与△ABE中
∵AB=DC
DF=BE
AE=CF
∴△ABE≌△CDF(SSS)
(2)∵△ABE≌△CDF
∴∠DCA=∠CAB
∴DC∥AB(内错角相等,两直线平行)
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