平面几何题M是△ABC边BC中点,MX⊥BC BY⊥AB CZ⊥AC .使MX:BY:CZ=1/2BC:AB:AC 求证XYZ三点共线且X是YZ中点?
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![平面几何题M是△ABC边BC中点,MX⊥BC BY⊥AB CZ⊥AC .使MX:BY:CZ=1/2BC:AB:AC 求证XYZ三点共线且X是YZ中点?](/uploads/image/z/14182259-59-9.jpg?t=%E5%B9%B3%E9%9D%A2%E5%87%A0%E4%BD%95%E9%A2%98M%E6%98%AF%E2%96%B3ABC%E8%BE%B9BC%E4%B8%AD%E7%82%B9%2CMX%E2%8A%A5BC+BY%E2%8A%A5AB+CZ%E2%8A%A5AC+.%E4%BD%BFMX%3ABY%3ACZ%3D1%2F2BC%3AAB%3AAC+%E6%B1%82%E8%AF%81XYZ%E4%B8%89%E7%82%B9%E5%85%B1%E7%BA%BF%E4%B8%94X%E6%98%AFYZ%E4%B8%AD%E7%82%B9%3F)
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