设F1,F2分别是椭圆的左右焦点,当a=2b时,点P在椭圆上,且PF1⊥PF2,/PF1-*/PF2/=2,求椭圆方程。x^2/a^2+y^2/b^2=1.
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![设F1,F2分别是椭圆的左右焦点,当a=2b时,点P在椭圆上,且PF1⊥PF2,/PF1-*/PF2/=2,求椭圆方程。x^2/a^2+y^2/b^2=1.](/uploads/image/z/14596315-43-5.jpg?t=%E8%AE%BEF1%2CF2%E5%88%86%E5%88%AB%E6%98%AF%E6%A4%AD%E5%9C%86%E7%9A%84%E5%B7%A6%E5%8F%B3%E7%84%A6%E7%82%B9%2C%E5%BD%93a%3D2b%E6%97%B6%2C%E7%82%B9P%E5%9C%A8%E6%A4%AD%E5%9C%86%E4%B8%8A%2C%E4%B8%94PF1%E2%8A%A5PF2%2C%2FPF1-%2A%2FPF2%2F%3D2%2C%E6%B1%82%E6%A4%AD%E5%9C%86%E6%96%B9%E7%A8%8B%E3%80%82x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2%3D1.)
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