计算log2sinπ/12+log2cosπ/12的值为log2sinπ/12+log2cosπ/12=log2(sinπ/12cosπ/12)=log2(1/2sinπ/6)=log2(1/4)=-2第一步是怎么来的?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 16:51:54
![计算log2sinπ/12+log2cosπ/12的值为log2sinπ/12+log2cosπ/12=log2(sinπ/12cosπ/12)=log2(1/2sinπ/6)=log2(1/4)=-2第一步是怎么来的?](/uploads/image/z/15103598-14-8.jpg?t=%E8%AE%A1%E7%AE%97log2sin%CF%80%2F12%2Blog2cos%CF%80%2F12%E7%9A%84%E5%80%BC%E4%B8%BAlog2sin%CF%80%2F12%2Blog2cos%CF%80%2F12%3Dlog2%28sin%CF%80%2F12cos%CF%80%2F12%29%3Dlog2%281%2F2sin%CF%80%2F6%29%3Dlog2%281%2F4%29%3D-2%E7%AC%AC%E4%B8%80%E6%AD%A5%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 16:51:54