已知P(x,y)是椭圆x^2/144+y^2/25=1上的点,则x+y的取值范围我想问用线性规划的方法做时:设x+y=ay=a-x ,a表示截距,即转化为求直线与椭圆有交点时截距的最值 我就是要问截距的最值该怎么求
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![已知P(x,y)是椭圆x^2/144+y^2/25=1上的点,则x+y的取值范围我想问用线性规划的方法做时:设x+y=ay=a-x ,a表示截距,即转化为求直线与椭圆有交点时截距的最值 我就是要问截距的最值该怎么求](/uploads/image/z/1644626-2-6.jpg?t=%E5%B7%B2%E7%9F%A5P%28x%2Cy%29%E6%98%AF%E6%A4%AD%E5%9C%86x%5E2%2F144%2By%5E2%2F25%3D1%E4%B8%8A%E7%9A%84%E7%82%B9%2C%E5%88%99x%2By%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%88%91%E6%83%B3%E9%97%AE%E7%94%A8%E7%BA%BF%E6%80%A7%E8%A7%84%E5%88%92%E7%9A%84%E6%96%B9%E6%B3%95%E5%81%9A%E6%97%B6%3A%E8%AE%BEx%2By%3Day%3Da-x+%2Ca%E8%A1%A8%E7%A4%BA%E6%88%AA%E8%B7%9D%2C%E5%8D%B3%E8%BD%AC%E5%8C%96%E4%B8%BA%E6%B1%82%E7%9B%B4%E7%BA%BF%E4%B8%8E%E6%A4%AD%E5%9C%86%E6%9C%89%E4%BA%A4%E7%82%B9%E6%97%B6%E6%88%AA%E8%B7%9D%E7%9A%84%E6%9C%80%E5%80%BC+%E6%88%91%E5%B0%B1%E6%98%AF%E8%A6%81%E9%97%AE%E6%88%AA%E8%B7%9D%E7%9A%84%E6%9C%80%E5%80%BC%E8%AF%A5%E6%80%8E%E4%B9%88%E6%B1%82)
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