求解三元一次方程:x+y-5z=16,y+z-5x=4,z+x-5y=-14

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求解三元一次方程:x+y-5z=16,y+z-5x=4,z+x-5y=-14
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求解三元一次方程:x+y-5z=16,y+z-5x=4,z+x-5y=-14
求解三元一次方程:x+y-5z=16,y+z-5x=4,z+x-5y=-14

求解三元一次方程:x+y-5z=16,y+z-5x=4,z+x-5y=-14
x+y-5z=16 (1)
y+z-5x=4 (2)
z+x-5y=-14 (3)
(1)+(2)+(3)
-3(x+y+z)=6
x+y+z=-2 (4)
(4)-(2)
6x=-6 x=-1
(4)-(3)
6y=12 y=2
(4)-(1)
6z=-18 z=-3
x=-1 y=2 z=-3

y+z-5x=4减去z+x-5y=-14等于y-x=3;
将z+x-5y=-14两端同时乘以5得5z+5x-25y=-70;
将5z+5x-25y=-70加上x+y-5z=16得x-4y=-9;
由x-4y=-9和y-x=3得 x=-1,y=2;
将x=-1,y=2代入y+z-5x=4中得到z=-3;
所以x=-1,y=2,z=-3;

x+y-5z=16,.........(1)
y+z-5x=4,...........(2)
z+x-5y=-14.........(3)
(1)-(2):6x-6z=12,化简:x=2+z.......(4)
(2)-(3):6y-6x=18,化简:y=3+x.......(5)
(1)-(3):6y-6z=30,化简:y=5+z.....(6)
...

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x+y-5z=16,.........(1)
y+z-5x=4,...........(2)
z+x-5y=-14.........(3)
(1)-(2):6x-6z=12,化简:x=2+z.......(4)
(2)-(3):6y-6x=18,化简:y=3+x.......(5)
(1)-(3):6y-6z=30,化简:y=5+z.....(6)
将(4)带入(3)z+z+2-5y=-14.....(7)
将(6)带入(7):2z-5*(5+z)=-16
z=-3
x=-1
y=2

收起

这样的题你采用消元思想,把三元先转化为二元,再把二元转化为一元掌握方法就好了