设严格单调函数y=f(x)有二阶连续导数,f(0)=0,其反函数x=§(y),且f(1)=1f'(1)=2,f"(1)=3,则§"(1)=?答案是-3/8,
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![设严格单调函数y=f(x)有二阶连续导数,f(0)=0,其反函数x=§(y),且f(1)=1f'(1)=2,f](/uploads/image/z/2622884-68-4.jpg?t=%E8%AE%BE%E4%B8%A5%E6%A0%BC%E5%8D%95%E8%B0%83%E5%87%BD%E6%95%B0y%3Df%28x%29%E6%9C%89%E4%BA%8C%E9%98%B6%E8%BF%9E%E7%BB%AD%E5%AF%BC%E6%95%B0%2Cf%280%29%3D0%2C%E5%85%B6%E5%8F%8D%E5%87%BD%E6%95%B0x%3D%C2%A7%28y%29%2C%E4%B8%94f%281%29%3D1f%27%281%29%3D2%2Cf%22%281%29%3D3%2C%E5%88%99%C2%A7%22%281%29%3D%3F%E7%AD%94%E6%A1%88%E6%98%AF-3%2F8%2C)
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