高二数学{排列组合二项式定理|(2-√3x)^100=a0+a1·x+a2·x^2+...+a100·x^100求:(1)a0 (2)a1+a2+...+a100(3)a1+a3+a5+...+a99 (4)(a0+a2+...+a100)^2-(a1+a3+...+a99)^2
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![高二数学{排列组合二项式定理|(2-√3x)^100=a0+a1·x+a2·x^2+...+a100·x^100求:(1)a0 (2)a1+a2+...+a100(3)a1+a3+a5+...+a99 (4)(a0+a2+...+a100)^2-(a1+a3+...+a99)^2](/uploads/image/z/3869540-44-0.jpg?t=%E9%AB%98%E4%BA%8C%E6%95%B0%E5%AD%A6%7B%E6%8E%92%E5%88%97%E7%BB%84%E5%90%88%E4%BA%8C%E9%A1%B9%E5%BC%8F%E5%AE%9A%E7%90%86%7C%EF%BC%882-%E2%88%9A3x%EF%BC%89%5E100%3Da0%2Ba1%C2%B7x%2Ba2%C2%B7x%5E2%2B...%2Ba100%C2%B7x%5E100%E6%B1%82%EF%BC%9A%281%29a0+%282%29a1%2Ba2%2B...%2Ba100%283%29a1%2Ba3%2Ba5%2B...%2Ba99+%EF%BC%884%EF%BC%89%28a0%2Ba2%2B...%2Ba100%29%5E2-%28a1%2Ba3%2B...%2Ba99%29%5E2)
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