lim x→0∫sin(t^2)dt]/(x^6-x^7)上限为x^2,下限为0

lim(x->0)∫sin(sqrt(t))dt/x^a, lim x→0∫sin(t^2)dt]/(x^6-x^7)上限为x^2,下限为0 最后一道题了,计算lim【x→0】 (∫【0→x^2】sin(t^2)dt)/x^6) 求极限 lim x→0 ∫sin t^2 dt / x^3 从2x积到0 lim x→0 ∫sin t^2 dt / x^3=?从2x积到0 lim x→0 ∫sin t^2 dt / x^3=?从x积到0 计算 lim(x→∞)sin^2x/∫（上限x^2,下限0）(t-cost)dt 计算 lim(x→∞)sin^2x/∫（上限x^2,下限0）(t-cost)dt lim(x→0)x^2tantx /∫(x,0)t(t+sint)dt 求lim(x趋向于0)1/(x^3)∫(上限为x下限为0)sin(t^2)dt lim x→0[∫上x下0 cos(t^2)dt]/x ; lim x→0[∫上x下0 ln(1+t)dt]/(xsinx) X→0,求lim［∫sin（t^2）dt］/(x^6+x^7) 上限为（1－cosx）,下限为0 lim(x→0)∫(上限为x,下限为0)sin(t^2)dt/x^3求极限过程,1/3 lim(x→0)[x∫(x→1)(cost/t^2)dt] lim(x→0)(x∫(x→1)cost/t^2dt) lim(x→0)[∫(0,x)(e^(t^2)-1)dt]/x^3 lim(x→0)[∫(0,x)(e^(t^2)-1)dt]/x^3 lim(x→o) (∫(0,x^2) √(1+t^2)dt) /x^2