已知方程x^2+bx+c=0有相异的两实数根,若k不等于0证明方程x^2+bx+c+k(2x+b)=0也有相异两实数根,且仅有一根在另一方程的两根之间.两根之间怎么证明啊?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 09:19:41
![已知方程x^2+bx+c=0有相异的两实数根,若k不等于0证明方程x^2+bx+c+k(2x+b)=0也有相异两实数根,且仅有一根在另一方程的两根之间.两根之间怎么证明啊?](/uploads/image/z/5077904-32-4.jpg?t=%E5%B7%B2%E7%9F%A5%E6%96%B9%E7%A8%8Bx%5E2%2Bbx%2Bc%3D0%E6%9C%89%E7%9B%B8%E5%BC%82%E7%9A%84%E4%B8%A4%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E8%8B%A5k%E4%B8%8D%E7%AD%89%E4%BA%8E0%E8%AF%81%E6%98%8E%E6%96%B9%E7%A8%8Bx%5E2%2Bbx%2Bc%2Bk%282x%2Bb%29%3D0%E4%B9%9F%E6%9C%89%E7%9B%B8%E5%BC%82%E4%B8%A4%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E4%B8%94%E4%BB%85%E6%9C%89%E4%B8%80%E6%A0%B9%E5%9C%A8%E5%8F%A6%E4%B8%80%E6%96%B9%E7%A8%8B%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B9%8B%E9%97%B4.%E4%B8%A4%E6%A0%B9%E4%B9%8B%E9%97%B4%E6%80%8E%E4%B9%88%E8%AF%81%E6%98%8E%E5%95%8A%3F)
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