设abc均为正数,且a+b+c=1 求证 1.a²b²+b²c²+c²a²≥abc 2.a²+b²设abc均为正数,且a+b+c=1求证1.a²b²+b²c²+c²a²≥abc2.a²+b²+c²≥9abc
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![设abc均为正数,且a+b+c=1 求证 1.a²b²+b²c²+c²a²≥abc 2.a²+b²设abc均为正数,且a+b+c=1求证1.a²b²+b²c²+c²a²≥abc2.a²+b²+c²≥9abc](/uploads/image/z/5283533-29-3.jpg?t=%E8%AE%BEabc%E5%9D%87%E4%B8%BA%E6%AD%A3%E6%95%B0%2C%E4%B8%94a%2Bb%2Bc%3D1+%E6%B1%82%E8%AF%81+1.a%26%23178%3Bb%26%23178%3B%2Bb%26%23178%3Bc%26%23178%3B%2Bc%26%23178%3Ba%26%23178%3B%E2%89%A5abc+2.a%26%23178%3B%2Bb%26%23178%3B%E8%AE%BEabc%E5%9D%87%E4%B8%BA%E6%AD%A3%E6%95%B0%2C%E4%B8%94a%2Bb%2Bc%3D1%E6%B1%82%E8%AF%811.a%26%23178%3Bb%26%23178%3B%2Bb%26%23178%3Bc%26%23178%3B%2Bc%26%23178%3Ba%26%23178%3B%E2%89%A5abc2.a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%E2%89%A59abc)
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