已知正方体ABCD—A*B*C*D*中,O是底面ABCD对角线的交点,求证:C*O∥平面AB*D*;A*C⊥平面AB*D*
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![已知正方体ABCD—A*B*C*D*中,O是底面ABCD对角线的交点,求证:C*O∥平面AB*D*;A*C⊥平面AB*D*](/uploads/image/z/5557646-38-6.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E4%BD%93ABCD%E2%80%94A%2AB%2AC%2AD%2A%E4%B8%AD%2CO%E6%98%AF%E5%BA%95%E9%9D%A2ABCD%E5%AF%B9%E8%A7%92%E7%BA%BF%E7%9A%84%E4%BA%A4%E7%82%B9%2C%E6%B1%82%E8%AF%81%EF%BC%9AC%2AO%E2%88%A5%E5%B9%B3%E9%9D%A2AB%2AD%2A%3BA%2AC%E2%8A%A5%E5%B9%B3%E9%9D%A2AB%2AD%2A)
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