求导数 y=e^-{cos(1/x)}^2下面两个不知从哪里复制连题目没看清

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/09 07:24:25
求导数 y=e^-{cos(1/x)}^2下面两个不知从哪里复制连题目没看清
x){=ϦnPMӭN/0ԯЬ3zEOv,ycՓ/}U/{.}ڱy/x>{ݳM ~&H`yr/cQ QB3UAH UqF :&>Yg9tnk]mѳOvv?ݰٌ 'tm]yӍSiM7( Ai*2&l\;! -FZ)^lݎM{D8#jn-$h0Tīf>$+

求导数 y=e^-{cos(1/x)}^2下面两个不知从哪里复制连题目没看清
求导数 y=e^-{cos(1/x)}^2
下面两个不知从哪里复制连题目没看清

求导数 y=e^-{cos(1/x)}^2下面两个不知从哪里复制连题目没看清
-{cos(1/x)}^2 *e^-{cos(1/x)}^2 *2*cos(1/x) *(-1/x^2) 我用手机,尽力了……总之就是复合倒,一个个倒


y '=e^[-cos(1/x)]²·{[-cos(1/x)]²} '
=e^[-cos(1/x)]²·2[-cos(1/x)]·[-cos(1/x)] '
=e^[-cos(1/x)]²·2[-cos(1/x)]·sin(1/x)·(1/x) '
=e^[-cos(1/x)]²·2[-co...

全部展开


y '=e^[-cos(1/x)]²·{[-cos(1/x)]²} '
=e^[-cos(1/x)]²·2[-cos(1/x)]·[-cos(1/x)] '
=e^[-cos(1/x)]²·2[-cos(1/x)]·sin(1/x)·(1/x) '
=e^[-cos(1/x)]²·2[-cos(1/x)]·sin(1/x)·(-1/x²)
=e^[-cos(1/x)]²·2cos(1/x)·sin(1/x)·1/x²
=e^[-cos(1/x)]²·sin(2/x)·1/x²

收起

y=e^-{cos(1/x)}^2
y'=e^[-cos(1/x)]^2*{[-cos(1/x)]^2}'
=e^[-cos(1/x)]^2*2sin(1/x)cos(1/x)*(1/x)'
=e^[-cos(1/x)]^2*2sin(1/x)cos(1/x)*(-1/x^2)