如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 20:13:22
![如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0](/uploads/image/z/7106778-18-8.jpg?t=%E5%A6%82%E4%BD%95%E8%AF%81%E6%98%8Elim%28sin%28%28n%2B1%29%5E%281%2F2%29%29-sin%28n%5E%281%2F2%29%29%29%3D0)
x){ީ/7>їQmaoȃr4m
lIפ_`gC]x)**t`FZ
Ũ^dǮ*ku.1ԁ i GAKPy&G >lx{)^"kҳ/.H̳
l^˙jy{E<Oz(ŲF' L m
如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0
如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0
如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0
sin((n+1)^(1/2))-sin(n^(1/2)) = 2sin[((n+1)^(1/2) - n^(1/2))/2]* cos[((n+1)^(1/2) + n^(1/2))/2]
因为|cos[((n+1)^(1/2) + n^(1/2))/2]|≤1,
sin[((n+1)^(1/2) - n^(1/2))/2]=sin[1/2 * 1/((n+1)^(1/2) + n^(1/2))]→0,n→∞,
所以sin((n+1)^(1/2))-sin(n^(1/2))→0,n→∞.
极限的代换,或者用定义,重要极限运用
如何证明lim(sin((n+1)^(1/2))-sin(n^(1/2)))=0
证明lim(sin/n)写出过程 谢谢打错了 证明 lim sin(1/n)=0 n区域无限大
证明lim (sin√n-sin√n+1)=0
求高数极限的证明lim n^(1/n)=1如何证明?
lim(n)^1/n=1证明
证明lim(n×sin1/n)=1
用∈-N定义证明下面死极限 lim(n→∞)sin N/(n+1)=0
级数(1/n)-sin(1/n)的敛散性如何证明
用∈-N极限定义证明x→o lim x*sin(1/x)=0
如何证明:lim(n->无穷)(1+1/n)^n = e
如何证明?利用夹逼准则证明lim(n趋于正无穷) n/a^n=0(a>1);
lim[nsin(1/n)+1/n(sin n)]=
lim(1/n)sin n (n→∞)
定义证明数列极限Lim (n^2/3 sin n!)/(n+1)^2=0n→∞希望有详细的过程.必须用定义证明哦~~
1.Xn=sin nπ/2 证明Xn极限不存在 2.用极限定义证明 证明 lim 1/√n=0
如何证明lim(sinx/x)=1?
lim (sin )/(n!+1),当n趋近无穷大时,
如何证明lim(n~正无穷)1/n2=0