f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 06:02:44
f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]
xMJPR4%$E ~h&bp0 p"8`.×B{ǹQʱہKE{.n֛yowqcrdU%[P'ѿ|?n^^OΈy>R34S^^sQTSm}.j|)J}jnR cr!BД"6 )h3R 2 FɴjBN6(,cEmQX(Xe"$@CA PEXRDdudx!

f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]
f(x)=[log2(x/8)][log(1/2)(4/x)]值域
令log(1/2)x=t∈[-3,1/2]

f(x)=[log2(x/8)][log(1/2)(4/x)]值域令log(1/2)x=t∈[-3,1/2]
这是答案