证明题:证明等式∫(a)(-a) f(x)dx=∫(a)(0)[f(-x)+f(x)]dx 其中(a)(-a)和(a)(0)是定积分中的上限和下限,所以这样写出,
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![证明题:证明等式∫(a)(-a) f(x)dx=∫(a)(0)[f(-x)+f(x)]dx 其中(a)(-a)和(a)(0)是定积分中的上限和下限,所以这样写出,](/uploads/image/z/7176485-29-5.jpg?t=%E8%AF%81%E6%98%8E%E9%A2%98%EF%BC%9A%E8%AF%81%E6%98%8E%E7%AD%89%E5%BC%8F%E2%88%AB%28a%29%28-a%29+f%28x%29dx%3D%E2%88%AB%EF%BC%88a%29%280%29%5Bf%28-x%29%2Bf%28x%29%5Ddx+%E5%85%B6%E4%B8%AD%EF%BC%88a%29%28-a%29%E5%92%8C%28a%29%280%29%E6%98%AF%E5%AE%9A%E7%A7%AF%E5%88%86%E4%B8%AD%E7%9A%84%E4%B8%8A%E9%99%90%E5%92%8C%E4%B8%8B%E9%99%90%2C%E6%89%80%E4%BB%A5%E8%BF%99%E6%A0%B7%E5%86%99%E5%87%BA%2C)
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