lim n→无穷 (6n-1)/(3n+1)=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 13:52:09
x)U{6WnWx,ON} 8OĴI*'V~
I>h{v|鄞3<ٽ4O
S4@55@4lby Am
5/.H̳Zo<;)/{yӎO',Dfؔfm9TVP@PA 9@v: *
lim n→无穷 (6n-1)/(3n+1)=?
lim n→无穷 (6n-1)/(3n+1)=?
lim n→无穷 (6n-1)/(3n+1)=?
分子分母同除以n,得 lim (6n-1)/(3n+1) = lim (6-1/n)/(3+1/n) = 2
罗比达法则吧。。6/3
lim n→无穷 (6n-1)/(3n+1)
=lim n→无穷 (6-1/n)/(3+1/n) 分子分母都除以n
=6/3
=2
lim n→无穷 (6n-1)/(3n+1)=?
lim(2^n+3^n)^1
(n趋向无穷)
lim[1^n+2^n+3^n]^(1/n)等于多少n→无穷
lim(n→正无穷)【n+2/n+1】的3n次方
求lim(n→无穷)(根号(n+1)-根号n)*根号n 的极限
lim(n^3+3^n)^1/n n趋于无穷
大一微积分求极限,谢谢帮忙咯~~~ lim(n-(n^2-n^3)^1/3))/n→无穷
求lim(n-无穷)(sinn!/(n!+1))
求两道极限题的解 lim(n->无穷)1+2+3+.+(n-1)/n^2lim(n->无穷)1+1/2+1/4+.+1/2^n
lim(1/n^3+(1+2)/n^3+...+(1+2+...+n)/n^3)n趋于无穷
lim(1^n+2^n+3^n)^1/n=?(n趋向无穷),怎么算出来的
1、lim n->无穷 根号[(n^4+n+1)-n^2]*(3n+4)
lim(n+2)(n-1)/3n^2+2n+1= n趋近于无穷
lim(n趋于无穷)[n(n+1)/2]/n方+3n的极限是多少?
lim根号n*n+n除以n+1=?(档n趋向于无穷)
lim n趋向于无穷 n[((n+1)/n)^n-e]
求极限~lim n[e-(1+1/n)^n] n->无穷lim n[e-(1+1/n)^n] n->无穷
lim(n到无穷)1+2+3+.+n/3n平方的极限?