作业帮lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
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lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
lim(1+2n+3n^2+……+2004n^2003)/(n^2003+2n^2002+……+2003n+2004)
当N趋向0时,答案为1/2004
当N趋向无穷时,可忽略分子分母中的低次幂,看高次幂系数（洛必达法则推论）,答案为2004
lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?（n趋近于无穷大）为什么不成立?
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