8log2^X-logX^2=log1/2^X

8log2^X-logX^2=log1/2^X 求y=log2 X+logx (2X)的值域 求y=log2 x+logx (2x)的值域 设函数f(x)=log2^x-logx^2(0 2log2^x+3logx^2-7=0 解方程：2log2 x-3logx 2+5=02log2 x-3logx 2 +5=0 不等式(2/3)^(logx(log2(3x))) 函数y=log2(x)+logx(2x)的值域是y=log2(x)+logx(2x)=log2(x)+logx(2)+logx(x)=log2(x)+logx(2)+1log2(x)与logx(2)互为倒数,故值域为(－∞,-1]∪[3,+∞) -1]是怎么来的 y=logx(2X)+log2X的值域y=log2(X)+logx(2X)的值域 解方程 log2(x-3)-log1/2(x)=2 log1/3 3 =2log2 x 求x 求函数y=log2(x/2)*logx(x/4),x属于[1,8]的最大值和最小值 求函数y=log2^x/2*logx^x/4,x属于［1,8］的最大值和最小值 log2(x)=-2/3 logx(3+2根号2) 求x.(1) log2(x)=-2/3 (2) logx(3+2根号2)=-2 。求x log2 x=logx 2 求x等于多少拜托了各位 函数y=log2(x)+logx(2x)的值域是 设数列f(x)=log2^x-logx^4(0 急...几题数学问题..用指数或对数解2log4(X+3)=1+log4(x+4)log2(x-1)+log2(x-4)=2(log2(X))^2=4logx(2) +2log2(x)-2logx(8)=-1只有第三题要计