怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 06:53:16
xRJ@)%3ɣ#I7ILTW*X[hbAp'
>~?Lt/Fڍpnι{A^,mtڕeQ
٧%a44HmE3!uMq؎6Rz[;kqr$~n7h\D,ki]_=*tmtC.ʇy AF|q*Nn:wn>f5^iFqЌVMVryy'>Tox3l
C3t"pT
F`nT%jy|^bz*wkc9AMLDHȺ[vtA!S#
mGAlMmCb)TXEQ^";bHl"+4G5#T5,K/u0
zï
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)
k为正整数)
当k=1时,即tan(π/3)=根号3
当k=2时,即tan(π/5)×tan(2π/5)=根号5
.
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
写得累死了
图片有点长,如果看不清再联系我
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1))=根号(2k+1)k为正整数)当k=1时,即tan(π/3)=根号3当k=2时,即tan(π/5)×tan(2π/5)=根号5.
三角函数证明题:tan(kA/2)tan(kB/2)+tan(kB/2)tan(kC/2)+tan(kA/2)tan(kC/2)=1,其中k是奇数
若tan(α/2)=[tan(β/2)]^3,tanβ=2tanφ,证明α+β=2kπ+2φ(k∈Z)
怎么证明sin2x=2tanx/(1+tan^2x)
怎么证明tan^2A+cot^2A不等于1
1-cosX/sinX=tan(X/2) 请问怎么证明,
证明tan(α)*tan(β)+tan(β)*tan(γ)+tan(α)*tan(γ)=1 (α+β+γ=π/2)详细一点
证明tanαtanβ+tanαtanγ+tanβtanγ=1,α+β+γ=π/2
tan(A/x)-1/tan(A/2)=-2/tanA这个怎么证明呢
怎么证明tanα×tan(90°-α)=1
tan(a/2)=tan^3(b/2) tanb=2tanx 证明a+b=2kπ+2x(k属于Z)
书上说tan(2kπ+α)=tanα,那可不可以tan(2kπ-α)=-tanα
证明1+sinx/cosx=tan(π/4+x/2)
证明:tanθ-(1/tanθ)=-2/tan2θ
SinX+1-cosX/sinX-1+cosX=1+tan(X/2)/1-tan(X/2) 请问怎么证明,
老师我想问一下 设a是n元列向量,a^Ta=k,A=aa^T,证明A^m+1=k^mA
怎么证明tanα>α.
已知tanα=2k+1,tanβ=2k-1,求cot(α-β)的值怎么计呀