dy/dx+y/xlnx=1

dy/dx+y/xlnx=1 y=xlnx+sinx-cosx求dx分之dy 求解微分方程xlnx dy +(y-lnx)dx =0,y(e)=1 xy^2 + xlnx = 4y x>o 求导（dy/dx) 求y=xlnx的微分dy y=sin2x+xlnx,求dy 高数,这个微分方程的通解怎么算?(ylnx-x)dx + (y+xlnx-x)dy = 0 dy/dx=1+1/(x-y) dy/dx=1-cos(y-x) dy/dx=x(1-y) dy/dx = 1/x-y y=xsiny+1 求dy/dx 微分方程,tanx dy/dx=1+y 已知y=xlnx求y'及dy 求下列微分方程的通解,1,dy/dx+3y=e的-2x次方；2,(x^2-1)y'+2xy=cosx;3,(xlnx)y'-y=3x^3ln^2x dy/dx-y=cosx dy/dx-y=xy5 dy/dx=x+y