x=1 y=2 do x=x*y y=y+1 loop while y
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 04:38:53
x)5T5RHWЪr*
r32sR*mR_`gCF`FJXٌO[;6zcɳikl@f 3V=h
x=1 y=2 do x=x*y y=y+1 loop while y
x=1 y=2 do x=x*y y=y+1 loop while y
x=1 y=2 do x=x*y y=y+1 loop while y
x=2;
do...while是先做再判断.
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
x=1 y=2 do x=x*y y=y+1 loop while y
X=2 Y=4 Do x=x*y y=y+1 Loop While y
化简 x / y(x+y) - y / x(x+y) =
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
x(x+y)(x-y)-y(y+x)(y-x)=(x-y)( )填空
y'/y=1/x
y+y'-2y=2x
微分方程y - 2y' + y = x
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+2y=2x+y+1=7x-y 求:2x-y?
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1