在三角形ABC中,2sin 2C·cos C-sin 3C=根号3 (1-cos C).(1) 求角C的大小;(2) 若AB=2,且sin C+sin(B-A) =2sin 2A,求△ABC的面积.
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![在三角形ABC中,2sin 2C·cos C-sin 3C=根号3 (1-cos C).(1) 求角C的大小;(2) 若AB=2,且sin C+sin(B-A) =2sin 2A,求△ABC的面积.](/uploads/image/z/1618192-64-2.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C2sin+2C%C2%B7cos+C-sin+3C%3D%E6%A0%B9%E5%8F%B73+%281-cos+C%29.%281%29+%E6%B1%82%E8%A7%92C%E7%9A%84%E5%A4%A7%E5%B0%8F%3B%282%29+%E8%8B%A5AB%3D2%2C%E4%B8%94sin+C%2Bsin%28B-A%29+%3D2sin+2A%2C%E6%B1%82%E2%96%B3ABC%E7%9A%84%E9%9D%A2%E7%A7%AF.)
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