Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/08 07:50:36
![Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)](/uploads/image/z/1831605-69-5.jpg?t=Ln6y%3D3xy%2C1%29%E6%B1%82dy%2Fdx%3B2%29%E6%B1%82d%5E2y%2Fdx%5E2%3B3%29%E5%B7%B2%E7%9F%A5d%5E2y%2Fdx%5E2%3D0%2C%E5%B0%B1%E6%BB%A1%E8%B6%B3%E7%9A%84%E7%82%B9%EF%BC%88x%2Cy%EF%BC%89)
xQMj@=IM'\V#h.DiGef&+-b潏n\j61Ѫ%zM7qPWǐǨ%[gEW[<&e^|X#}ro?
bpzblчO;lQF_R
fC{t'foYͩtR(A
`k
)8<CV[28s7O _
ᢡ TȀm
Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)
Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)
Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)
y跟x是成函数关系吧
那么第一个就是求导了
两边同时对x求导
令dy/dx为a
则6a/6y=3y+3xa
a=3y^2/1-3xy
第二问就是再导多一次
令d^2y/dx^2=b
by-a^2/y^2=3a+3a+3xb
b=aby^2+a^2/y-3xy^2
第三个问就是求出x与y的关系就可以了,那应该是曲线轨迹,而不是一个点而已
Ln6y=3xy,1)求dy/dx;2)求d^2y/dx^2;3)已知d^2y/dx^2=0,就满足的点(x,y)
x^2+xy+y^3=1,求dy/dx
求通解,dy/dx-3xy=xy^2
求dx/dy-3xy=xy^2的通解
dx/dy+xy=-1,求通解
求微分方程dy/dx+2xy=3x
dy/dx=3xy+xy^2.求y.
设e^xy-xy^2=Siny,求dy/dx
求dy/dx+2xy+xy^4的通解求dy/dx+2xy+xy^4=0的通解
求微分方程y^3 dx -(1-2xy^2)dy=0的通解.
求x^2(dy/dx)+3xy=1的通解
求微分方程 dy/dx=y^4/(1-2xy^3)
求一阶微分方程dy/dx=1/(xy+x^2*y^3)通解
求方程dy/dx=(1+y^2)/(xy+yx^3)的解.
用隐求导法求 xy^2 - yx^2 = 3xy 求dy/dx
伯努利方程求通解:dy/dx-3xy=xy^2
y^2+xy+3x=9求:dy/dx,于是得到2y dy/dx+1 y+dy/dx+3=0,我不明白怎将y看成x的函数?
已知sin(xy)=x^2,求 dy/dx=