dy/dx+y/x=x^2,y(1)=0求解微分方程要步骤

(x^2)dy+（y^2)dx=dx-dy dy/dx=x+y dy/dx,y=(1+x+x^2)e^x dy/dx=x(1+y^2)/y通解 dy/dx=1+1/(x-y) dy/dx=1-cos(y-x) dy/dx=x(1-y) dy/dx = 1/x-y 微分方程 dy/dx=(-2x)/y dx/dy=x/y+[cos（x/y）]∧2,y（0）=1 y(x + y + 1) dx + (x + 2y) dy = 0:运用正合方程式求解 dy/dx=(e^x+x)(1+y^2)通解 (x+y)dy+(x-y)dx=0求通解 dy/dx=2y/x+3x/2y x^y-y^x=2,求dy/dx 求dy/dx=(x-y+5)/(x+y-2) （-2x-y+9)dy=(-y+x+3)dx x=y的y次方(y>0),则dx/dy=,dy/dx